[ تمت الإجابة ]سؤال : كيف يتم تنسيق الخرج في ++C

تفضلي :

#include<cmath>
#include<iostream>
using namespace std;

int main() {
    long result;
    int a, b, count = 0, itoa[64];
    cout << "Enter the First Number : ";
    cin >> a;
    cout << "Enter the Second Number : ";
    cin >> b;
    result = a*b;
    while (result > 9) {
        itoa[count] = result % 10;
        result = (int) result / 10;
        count++;
    }
    itoa[count] = result;
    cout << "The Result is : ";
    for (int i = count; i >= 0; i--)
        cout << itoa[count - i] << " ";
    return 0;
}

in c lang like this

...const int size = 20;char buffer[size];int n = snprintf(buffer, size, "%d", c); // use the safe function: snprintf, do not use sprintfassert(n >= 0);   // format error is indicated by a negative valueassert(n < size); // n is the number of characters written, excluding the terminating null-characterfor(int i = 0; i < n; ++i) cout << buffer << ' ';

What it does:
1) write the c into a character array (buffer).
2) make sure you do not write past the buffer end (use snprintf[^])
3) make sure the conversion does not need more characters than provided by the buffer (take in count the return value and assert[^] that writing was not expecting a larger buffer).
4) finally write each character followed by a space

++c

like this

...
ostringstream oss;
oss << c;
assert(oss.good()); // no format error
// C++11 version
for(char ch: oss.str()) cout << ch << ' ';
// iterator based version
string s = oss.str();
for(string::iterator it = s.begin(); it != s.end(); ++it) cout << *it << ' ';

شكرا كتير على جهودكم

اريد تبسيط الفكره اكثر لكي افهم الخوارزمية

الفكره الاساسية ان المستخدم يدخل قيمة متغير نوع int

ونفس القيمة اللي بيدخلها المستخدم تظهر ناتج بس بين الرقم والرقم مسافه

مثال

قيمة متغير تساوي 3868

الناتج الاخير 8 6 8 3