السلام عليكم و رحمة الله و بركاته
عملت كود php لإدخال البيانات في الداتابيس , لكن الكود لا يعمل و يخرج رساله
Can not execute the query
<?php
// Connect MySql
$link = mysql_connect('localhost', 'root', '');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
// to select a data base already created
$db_selected = mysql_select_db('Studio-ghibli',$link);
if (!$db_selected)
{
die ("can not use".'Studio-ghibli'.":".mysql_error());
}
echo '<p>successfully Selected (Studio-ghibili DB)</p>';
// for inserting data
$fname = $_POST['FilmName'];
$Director = $_POST['Director'];
$rate=$_POST['rate'];
$sql = "INSERT INTO feature-films (ID,FilmName,Director,rate)VALUES(0,'$fname','$Director','$rate')";
if (@mysql_query($sql))
{
print'<p>Your Data have been added successfully </p>';
}
else
{
print'<p>Can not execute the query</p>';
}
mysql_close();
?>و هذا الكود لتحديد الداتابيس
<?php
$username="root";
$password="";
$database="Studio-ghibli";
mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM feature-films";
$result=mysql_query($query);
$num=mysql_numrows($result);
mysql_close();
echo "<b><center>Database Output</center></b><br><br>";
$i=0;
while ($i < $num) {
$fname=mysql_result($result,$i,"FilmName");
$Director=mysql_result($result,$i,"Director");
$rate=mysql_result($result,$i,"Rate");
echo "<br>$fname<br>
$Director<br>
$rate<br>";
$i++;
}
?>أرجو المساعده و جزاكم الله خيراً (),